Donald Trump has a double-digit lead over Hillary Clinton in Indiana, according to a Monmouth University survey released Wednesday.
The poll found that Trump leads Clinton 47 percent to 36 percent in the state. Ten percent of voters said they support Libertarian Gary Johnson and 5 percent said they are undecided.
Independent voters are split between the two major nominees, with 38 percent supporting Trump and 34 percent backing Clinton.
A third of voters in Indiana said they view Trump favorably compared to just over a quarter who said the same about Clinton.
Nearly 60 percent of voters said they approve of the job Trump’s vice presidential nominee, Gov. Mike Pence, is doing for their state and 35 percent said that they disapprove.
Meanwhile, former Democratic Sen. Evan Bayh, who, leads his Republican challenger Rep. Todd Young 48 percent to 41 percent.
Mr. Obama won Indiana in 2008 against John McCain but lost the state to Mitt Romney in the 2012 election.
Recent polls show Clinton maintaining leads in other key swing states and nationally.
The Monmouth poll surveyed 403 Indiana residents likely to vote in November’s election between August 13 and 16 with a 4.9 percentage point margin of error.